1樓：匿名使用者
private sub command1_click()msgbox sum(3)
end sub
function cf(n as long) as longcf = n ^ 4
end function
function sum(n as long) as longdim result as long
dim i as long
result = 0
for i = 1 to n
result = result + cf(i)next
sum = result
end function
編寫函式，計算m的n次方，然後編寫主函式呼叫並驗證。
2樓：兄弟連教育北京總校
input "m^n,m=,n=」;m,ni=1do while im=m*m
wend
print "m^n";"m=",m
vb中編寫乙個求階層的函式,呼叫函式求s=1!+1/2!+1/3!+1/4!+……+1/n!。 5
3樓：聽不清啊
private sub command1_click()dim n as integer, i as integern = cint(inputbox("n="))for i = 1 to n
s = s + 1 / fact(i)
next i
msgbox ("s=1!+1/2!+1/3!+1/4!+……+1/" & n & "!=" & s)
end sub
function fact(byval n as integer) as double
dim f as double
f = 1
while n > 1
f = f * n
n = n - 1
wend
fact = f
end function
4樓：匿名使用者
private function ss(byval n as integer) as double
dim i as integer
dim t as long
dim s as double
t=1s=0
for i=1 to n
t=t * i
s=s+(1+1/t)
next i
ss =s
end function
使用函式的巢狀功能求1!+2!+3!+4!+……+n!的值
5樓：湯訓
int jc(int n)
main() .
6樓：匿名使用者
void func(unsigned int n)void functotalvalue(unsigned int n)
return val;
} //func的遞du歸可zhi以用循dao環內替代容
7樓：匿名使用者
函式巢狀???是遞迴吧!
專int jc(int n)
main()
8樓：生日顏色
declare@
版s int
declare@權a int
declare@b int
set@n=1
set@b=0
while@n<=7
begin
set@s=1
set@a=@n
while@a>1
begin
set@s=@s*@a
set@a=@a-1
endset@b=@b+@s
set@n=@n+1
endselect@b
編vb程式計算1-1/2!+1/3!-1/4!+···+（-1)^(n-1)*(1/n!)的和？
9樓：匿名使用者
private sub form_click()dim i as long, p as double, s as double, t as integer
t = 1
p = 1
dim n as integer
n = inputbox("請輸來入
源乙個整數:")
for i = 1 to n
p = p * i
s = s + t / p
t = -t
next
print format(s, "0.0000000")end sub
10樓：匿名使用者
private sub command1_click()dim s as single
dim n as integer
n = val(text1)
for i = 1 to n
s = s + (-1) ^ (n - 1) * 1 / nnext
print "s = "; s
end sub
vb編寫函式，實現計算1^3+2^3+3^+……+20^3
11樓：匿名使用者
private sub form_load()for i = 1 to 20
s = s + i ^ 3
next
msgbox s
end sub
c語言呼叫函式求s=1^1+2^2+3^3+4^4………n^n 5
12樓：匿名使用者
^#include
long power(int n)//計算n^n;int main(int argc, char *argv)輸入3n=3時,sum=1^1+2^2+3^3+4^4………n^n=32!
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編寫函式mypow函式的功能是計算a的n次方在主函式
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